Limits, it is becoming increasingly important for players to take advantage ofĪspects of the sport like spin and velocity. In racquet technology allowing the tennis ball to be literally stretched to its Like every other sport, tennis is governed by the laws of physics. Tennis, players often appear to hit shots that defy physics, whether it’sĪ groundstroke that resists gravity-floating through the air withīackspin-or a serve that leaves the racquet at an incredible speed. Only for it to curve back toward the pins for a strike? How does OlympicĬhampion figure skater Kristi Yamaguchi increase the speed of her spin just byĪdjusting her posture? The answers to these questions, and many more, lie in This article focuses on the generation of spin on a tennis ball, how to maximize the power of a shot, and finding the “sweet spot” on the racquet.Īthlete and wonder how they are able to perform such an astonishing feat? Howĭoes bowling legend Pete Weber throw the ball dangerously close to the gutter, But it all becomes much simpler when you understand the physics behind tennis. Cheers.The shots of a professional tennis player may look like magic, seemingly defying the laws of science before your eyes. And if you plug those into your calculator, you should get 960 newtons. And the bottom becomes four times ten to the minus three. We get two times the mass, which we said was 0.06. And that's equal to this twice times the mass times the speed V. So this should be four times ten to the minus three seconds. If you look at the units here, this is milliseconds. So we just calculated that the area under the curve was equal to F max times four. And now it looks like we have all the information we need. Alright? So we'll write this as F max times four seconds. So the area is just F max times delta T, where now delta T is going to be zero to four. And so if I take this last triangle and move it over here, I can fill in this gap right here. Now if I want to calculate the area under this whole thing, one thing that I notice is this first triangle is exactly the same as the last triangle. And let's say we want to figure out what that F max is equal to. And we're going to say that it does this sort of shape. So if we know those numbers, m and V, then we can relate it back to the force because the force is related to this area under the curve. And we're going to say that's a negative. But what we do know is that V initial is to the left. If I made both of those V's, this whole thing would go to zero. And in the case of something like a super ball, let's say that it goes in with speed V and comes out with speed V. And in this case, we know what? If it goes in with Vi, comes out with Vf, then delta P is mVf minus mVi. But impulse J is simply change in momentum, delta P. That's equal to the area under the curve. And in fact, the area under the curve tells us the impulse that is delivered to the ball. So if we think about this problem, what we know is the area under the curve is important. And then it springs back off and goes back down to zero. It's fairly constant for some amount of time while the ball is compressed. It ramps up as the ball is getting compressed against the wall. So let's say the force does something like this. And we want to figure out something about that force. And while it's in contact with the wall, we can map out the force as a function of time. We have an object, say a tennis ball, that is going to hit the wall and bounce back off the wall. Let's take a look at one of your homework problems.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |